At $t = 2$ s, $a = 6(2) - 2 = 12 - 2 = 10$ m/s$^2$
Acceleration, $a = \frac{dv}{dt} = \frac{d}{dt}(3t^2 - 2t + 1)$ practice problems in physics abhay kumar pdf
Given $u = 20$ m/s, $g = 9.8$ m/s$^2$
$\Rightarrow h = \frac{400}{2 \times 9.8} = 20.41$ m At $t = 2$ s, $a = 6(2)
$= 6t - 2$
Acceleration, $a = \frac{dv}{dt} = \frac{d}{dt}(3t^2 - 2t + 1)$
$\Rightarrow h = \frac{400}{2 \times 9.8} = 20.41$ m
